(b^2-12b-5)/2b

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Solution for (b^2-12b-5)/2b equation: 


b in (-oo:+oo)

b*((b^2-(12*b)-5)/2) = 0

b*((b^2-12*b-5)/2) = 0

(b*(b^2-12*b-5))/2 = 0

b^2-12*b-5 = 0

b^2-12*b-5 = 0

DELTA = (-12)^2-(-5*1*4)

DELTA = 164

DELTA > 0

b = (164^(1/2)+12)/(1*2) or b = (12-164^(1/2))/(1*2)

b = (2*41^(1/2)+12)/2 or b = (12-2*41^(1/2))/2

(b-((12-2*41^(1/2))/2))*(b-((2*41^(1/2)+12)/2)) = 0

(b*(b-((12-2*41^(1/2))/2))*(b-((2*41^(1/2)+12)/2)))/2 = 0

( b-((12-2*41^(1/2))/2) )

b-((12-2*41^(1/2))/2) = 0 // + (12-2*41^(1/2))/2

b = (12-2*41^(1/2))/2

( b-((2*41^(1/2)+12)/2) )

b-((2*41^(1/2)+12)/2) = 0 // + (2*41^(1/2)+12)/2

b = (2*41^(1/2)+12)/2

( b )

b = 0

b in { (12-2*41^(1/2))/2, (2*41^(1/2)+12)/2, 0 }

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